DARBS UN ENERĢIJA. - lvg.lv

DARBS UN ENERĢIJA. - lvg.lv

DARBS UN ENERIJA. Darb izmantoti A. ablovska sastdtie uzdevumi ar atrisinjumiem un veidots animcijas. Elektromotors vienmrgi pace 10kg smagu kravu 6m augstum 10 sekunds. a) Cik lielu darbu padara motors ? b) Cik lielu jaudu attsta motors ? c) Cik liels ir motora lietderbas koeficients, ja dzinja piln jauda ir 80 W? Elektromotors vienmrgi pace 10kg smagu kravu 6m augstum 10 sekunds. a) Cik lielu darbu padara motors ? Dots: m = 10 kg h = 6m A = Fl F= mg l = h t = 10s Np = 80W A-? A = mgh A = 10106 = 600J b) Cik lielu jaudu attsta motors ? A

600 N= t N = 10 = 60W c) Cik liels ir motora lietderbas koeficients, ja dzinja piln jauda ir 80 W? = Nl Np = 60 80 = 0,75 F mg h Slps plaknes garums ir 10m un augstums 5m. Lai pa to vienmrgi augup vartu pavilkt kasti, kuras masa 40 kg, tai jpieliek 300N spks. Aprint slps plaknes lietderbas koeficientu.

Slps plaknes garums ir 10m un augstums 5m. Lai pa to vienmrgi augup vartu pavilkt kasti, kuras masa 40 kg, tai jpieliek 300N spks. Aprint slps plaknes lietderbas koeficientu. Dots: l = 10m h = 5m m = 40kg F = 300N -? = Al Ap Al= mg h F = mg Fv Ap = F v l l =

mgh Fv l 40105 = 300 10 h mg = 0,67 = 67% Celtnis prvieto vertikli augup kravu, kuras masa ir 0,5t. Aprint celta vilcjspka veikto darbu, ja kravu prvieto 6m augstum : a) vienmrgi ; b) ar patrinjumu 1 m/s2. Celtnis prvieto vertikli augup kravu, kuras masa ir 0,5t. Aprint celta vilcjspka veikto darbu, ja kravu prvieto 6m augstum : a) vienmrgi ;

Dots: m = 500kg h = 6m a1 = 0m/s2 a2 = 1m/s2 A-? y b) ar patrinjumu 1 m/s2. A = F s cos s=h a) Fv = mg Fv = 0; cos = 1 A = Fv h A = mgh h mg

A = 500106 = 30000 J y b) A = Fv h F=ma Fv+ mg = m a Fv - mg = m a Fv = ma + m g A = m (a + g) h / projekcija uz y ass / Fv = m ( a+g) A = 500 (1 + 10) 6 = 33000 J a Fv mg h

Pabeigt teikumu! 1) Lielumu, kas rda darba veikanas trumu, sauc par . jaudu. ... 2) Ja ermeu sistm darbojas berzes spks, tad sistmas piln mehnisk enerija . samazins. ..... 3) Ja ermenim piemt spja veikt darbu, tad tam piemt .enerija. .... 4) Ja ermenim pieliktais rejais spks veic pozitvu darbu, tad ermenim tiek pievadta enerija, kas vienda ar .darbu. .... 5)Sistmas piln mehnisk enerija nav konstanta, ja ermeu sistm darbojas ar . . . . . berzes spki. 6) Ja vienda tilpuma svina un dzelzs lodtes pace viend augstum, tad lielka potencil enerija ir . . . . lodtei. svina No neliela augstuma brvi krt lodte. Kur no grafikiem raksturo potencils enerijas atkarbu no augstuma. a) Ep b)

Ep h h h Pareiza atbilde. c) Ep d) E = mgh Ep h h h

; ar E Lodte ripo pa slpu virsmu bez skuma truma. Kur grafiks attlo lodtes kintisks enerijas maiu atkarb no laika? a) Ek b) Ek t t Pamatojums: c) Ek d) Ek

mv2 Ek = 2 v = at t Pareiza atbilde. t m a2 t 2 Ek = 2 Lodte ripo pa slpu virsmu bez skuma truma. Kur grafiks attlo lodtes potencils enerijas maiu atkarb no laika? a) Ep b) Ep h1

Pareiza atbilde. h t t Pamatojums: c) Ep d) Ep E = mgh at2 h1 = 2 h = H h1 h=H

t t at2 2 H Ja automobia trums ir 25 km/h, tad bremzanas ce ir s. Cik gar ir bremzanas ce, ja automobia trums ir 100km/h. Ek = Ab / Ab- bremzanas darbs / mv2 = Fb s 2 Ja v 4 reizes, tad s mv2 s=

2 Fb 42 = 16 reizes /pieaug / Neliela lodte, kuras masa 100g, sk ripot pa liektu virsmu bez berzes. Aprint lodtes trumu punkt B un punkt C. A Dots: m= 0,1kg h1 = 4m C h2 = 3m 4m vB- ? 3m vc- ? B (.) A E = Ep = mgh1

(.) B E = Ek (.) C E = Ek + Ep Ek = 4J Ek = 4 3 = 1J Ep = 0,1104 = 4 J mv2 Ek= 2 v= E = 4 J /piln enerija / 2Ek m Ek = E - Ep Ep =mgh2

mv2 Ek= 2 v= 2Ek m v= 24 0,1 = 8,94m/s Ep =0,1103 = 3J v= 21 = 4,47 m/s 0,1` ermenis, kura masa15kg, sk krist vertikli lejup no 30m augstuma. Aprint gaisa pretestbas prvaranai veikto darbu, ja ermenis

sasniedz zemi ar trumu 10 m/s. ermenis, kura masa15kg, sk krist vertikli lejup no 30m augstuma. Aprint gaisa pretestbas prvaranai veikto darbu, ja ermenis sasniedz zemi ar trumu 10 m/s. Dots: m = 15kg h = 30m v = 10m/s Ep Ab = Ep - Ek Ep = mgh A mv Ek= 2 2 Ab - ? mv2

Ab = mgh 2 15102 Ab = 151030 = 4500 750 = 3750J 2 Ek ermenis , kura masa 7kg, sk sldt pa slpo plakni. Plaknes garums16m un slpuma leis 30. Aprint aj proces izdalto siltuma daudzumu, ja ermea trums pie plaknes pamata ir 5m/s. ermenis , kura masa 7kg, sk sldt pa slpo plakni. Plaknes garums16m un slpuma leis 30. Aprint aj proces izdalto siltuma daudzumu, ja ermea trums pie plaknes pamata ir 5m/s. Dots: m = 7 kg l = 16 m = 30 v = 5 m/s Q-? Ep Q = Ep - Ek Q

mv2 Q = mgh - 2 h l Ek 752 Q = 7108 = 560 87,5 = 472,5 J 2 h = sin l h = l sin h = 160,5 = 8m Celtnis 1 mint vienmrgi pace 5m augstum kravu, kuras masa 2t .Celta lietderbas koeficients ir 80%.Apreint darbu, ko veic celta elektrodzinjs. Celtnis 1 mint vienmrgi pace 5m augstum kravu, kuras masa 2t .Celta lietderbas koeficients ir 80%.Apreint darbu,

ko veic celta elektrodzinjs. Dots: t = 1min h = 5m m = 2t = 80% Ap - ? 60s 2000kg 0,8 Al = A p Al = Ep= mgh Al Ap = mgh Ap = Ap = 2000105 = 125000 J = 125 kJ

0,8 F mg h Liepjas Valsts 1. imnzijas fizikas sk. A.ablovskis .

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