# Question - IYPT Archive

Problem 14 Magnetic Spring Reporter: Hsieh, Tsung-Lin Question Two magnets are arranged on

top of each other such that one of them is fixed and the other one can move vertically. Investigate oscillations of the magnet. Outline Horizontal Dimension (Force field) Experimental Setup Experimental Result Vertical Dimension

Analysis Summary Horizontal Dimension (Force field) Experimental Setup Experimental Result Vertical Dimension Analysis Summary

Forces Magnetic force Gravitational force Dissipative force Force Field Cylindrical magnet can be interpreted by a

magnetic dipole. When the upper magnet is at the unstable equilibrium position, the separation is said to be r0. Fig. Potential diagram for the upper magnet

Horizontal Dimension Experimental Setup Experimental Result Vertical Dimension Analysis Summary

Tube Confinement Tube Top view Large friction Start with large amplitude Side view

Side view Beam Confinement Almost frictionless Start with small amplitude Experimental Procedures

Perturb the upper magnet Record by camera Change initial amplitude Change length (l) Change mass (m) Horizontal Dimension Experimental Setup

Experimental Result Vertical Dimension Analysis Summary Tube Confinement C=6.4*10-4 J-m m=5.8 g l=1.00 cm

y =12.2 cm 0 v0=0 cm/s String Confinement C=5.4*10-5 J-m m=5.7 g

l=1.00 cm y =23 cm 0 v0=0 cm/s Experimental Results

with Period The curve at the bottom turning point is sharper Amplitude decays Period reduces Beam Confinement C=6.4*10-4 J-m

l=1.00 cm m magnet=5.8 g mbeam=10.0 g Beam length=31.9 cm y =0.88 cm

0 v0=0 cm/s Experimental Results Almost frictionless Periodic motion

T=0.17 0.00 s Horizontal Dimension Experimental Setup Experimental Result Vertical Dimension

Analysis Summary Magnetic Force vs. Separation Verifying the Equation l r l

Horizontal Dimension Experimental Setup Experimental Result Vertical Dimension Analysis Analytical Numerical Summary

Equation of Motion : Moment of Inertia Small Amplitude Approximation The force can be linearized. Small oscillation period Ts =

Finite Amplitude , Thus, there are only three parameters , , .

Numerical Solution Finite oscillation period T=f (Ts, , ) Comprehensive Solution of

1.01.0 y0 T y0 0 T Ts l large T X l 1.4

2.2 Usage of the Solution Diagram C=6.39*10-4 J-m l=1.00 cm m magnet=5.8 g Period (T)

mbeam=10.0 g Beam length=31.9 cm y =0.88 cm 0

v0=0 cm/s Finite Damping Horizontal Dimension Experimental Setup Experimental Result Vertical Dimension Analytical Modelling Numerical Modelling

Summary Summary Confinements Tube String Beam Analytical Modelling Numerical Modelling

1 . 0 1 . 4 Thanks for listening!

Small Amplitude Approximation S.H.O., Damping force proportional to velocity: y ( t ) y0 e , where

b t 2 cosd t 2 2

b d o Finite Amplitude Constant friction

Both term Damping force proportional to velocity

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